(a) x 2 y 2 2xy (b) x 2 y 2 – xy (c) xy 2 (d) 3xy polynomials512v 5 99w 5;We think you wrote (x^3y^3)/(x^23xy2y^2)•(x^2xy6y^2)/(x^22xy3y^2)÷(x^2xyy^2)/(2x^22xy) This deals with factoring binomials as the sum or difference of
Solved Expand X X Y 3 3xy X Y
